Photovoltaics - Power and Energy
Calculator for the conversion of the peak power of a photovoltaic system, the produced energy per year and the yield factor. The peak power has the unit Wp, watt-peak. This is the maximum power at ideal conditions. The unit for the energy per year is Wh, watt hours. The yield factor, amongst others, depends on sunshine duration and the angle to the sun.
Here can be calculated, how much energy can be expected with a system of a certain size or, from measured values, what the yield factor of an existing system is. Please choose the units and enter two values, the third will be calculated.
1 kW = 1000 W, 1 MW = 1000 kW, 1 GW = 1000 MW, W = watt, kW = kilowatt, MW = megawatt, GW = gigawatt
Example: a power system with 6 kWp, producing 5700 kWh per year, has a yield factor of 950.
The yield factor is calculated as energy divided by peak power. Since energy is given in watt hours and power in watts, the yield factor is given in watt hours per watt, Wh/W. This can of course be abbreviated to hours. This value in hours can be interpreted to reflect the yield if the photovoltaic system had generated electricity at peak power for this number of hours in a year and none at all for the rest of the hours of year. An average year has 8765.8 hours. If the system were to deliver peak power for about a ninth of the time, it would generate its annual yield. This low value is of course due to the fact that the system virtually never reaches its peak power, so the actual average power achieved corresponds to that fraction. See average power.
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